Physics projectile formula
Tuesday, April 8th, 2008A 0.11 kg ball is thrown straight up into the air with an initial velocity of 26 m/s
Find the momentum of the ball halfway to its maximum height on the way up.
V0 = 26 m/s
g=9.8 m/s^2
Max Height = V^2/2g
= 26^2 / 2*9.8
= 676 /19.6
= 34.489 meters
Halfway up is 1/2 this number or 17.2445 meters
Use the equation for height in terms of time
and solve for t
Height = Vt - 1/2 gt^2
17.2445 = 26t -1/2 (9.8)t^2
4.9t^2-26t+17.2445=0
Use the quadratic formula
( -b +- SQRT(b^2-4ac))/2a
to solve for roots
Roots are 0.777(ball on way up) and 4.52(ball on way down)